6c^2-35c-18=0

Solution for 6c^2-35c-18=0 equation:

6c^2-35c-18=0

a = 6; b = -35; c = -18;
Δ = b2-4ac
Δ = -352-4·6·(-18)
Δ = 1657
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$c_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-35)-\sqrt{1657}}{2*6}=\frac{35-\sqrt{1657}}{12}
$
$c_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-35)+\sqrt{1657}}{2*6}=\frac{35+\sqrt{1657}}{12}
$